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11-07-2016
Chemistry

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If 234 mL of water at 35*C loses 1412 calories of heat, what is the new temperature of the water following this heat loss?

If 234 mL of water at 35C loses 1412 calories of heat what is the new temperature of the water following this heat loss class=

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Edufirst Edufirst

20-07-2016

Heat loss, Q = 1412 cal
mass of water, V x d = 234 ml x 1 g/ml = 234 g
Specific heat, C = 1 cal/g °C

Q = mCΔT ⇒ΔT = Q / mC

To - Tf = Q / mC
Tf = To - Q / mC

Tf = 35° - 1412 cal/[234 g * 1cal/g°C]

Tf = 35° - 6.03°

Tf = 28.97 °C

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