creamerbarb
creamerbarb creamerbarb
  • 12-07-2016
  • Chemistry
contestada

show the equation how many grams of Mg(OH)2 would be produced from 4 mol KOH?

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Willchemistry
Willchemistry Willchemistry
  • 17-07-2016
Mole ratio:

MgCl₂ + 2 KOH = Mg(OH)₂ + 2 KCl

2 moles KOH ---------------- 1 mole Mg(OH)₂
4 moles KOH ------------------- moles Mg(OH)₂

moles Mg(OH)₂   = 4 x 1 / 2

= 2  moles of   Mg(OH)₂

molar mass Mg(OH)₂ = 58g/mol

mass of   Mg(OH)₂ = n x mm

mass of  Mg(OH)₂ = 58 x  2

= 116 g of  Mg(OH)₂

hope this helps!
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