tianamfarmer tianamfarmer

14-07-2016
Mathematics

contestada

evaluate
9C5
and
11P4
.

Respuesta :

konrad509 konrad509

14-07-2016

[tex]9C5=\dfrac{9!}{5!4!}=\dfrac{6\cdot7\cdot8\cdot9}{2\cdot3\cdot4}=6\cdot7\cdot3=126\\\\ 11P4=\dfrac{11!}{7!}=8\cdot9\cdot10\cdot11=7920[/tex]

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