Answer:
[tex]y=-\frac{3}{4}x+1[/tex] is the equation of line required in slope-intercept form.
Step-by-step explanation:
First of all compute the slope: [tex]\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]m=\frac{-5-1}{8-0}=-\frac{3}{4}\\\\\mathrm{Then\: find \:the \:y-intercept \:as:}\\\\y=\left(-\frac{3}{4}\right)x+b\:\quad\rightarrow\quad b=1\\\\\mathrm{So \:the\: equation\: of\: line\: is\: as:}\\\\y=-\frac{3}{4}x+1[/tex]
Thanks!
