Answer: 0.14 M
Explanation:
Given that,
Amount of moles of KCl (n) = 0.014
Volume of aqeous solution (v) = 0.100 L
Concentration of KCl solution (c) = ?
Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence
c = n / v
c = 0.014 moles / 0.100 L
c = 0.14 M (note that 0.14 M is same as concentration in mole per litres which is molarity)
Thus, the concentration of a .100 L aqueous solution that contains .014mol of KCL is 0.14 M
