nitou0413 nitou0413
  • 14-04-2020
  • Mathematics
contestada

What is the area of the regular pentagon below?
2.4 yd
3.5 yd
O
O
A. 42.0 yd
B . 30.6 yd2
OC. 8.4 yd

What is the area of the regular pentagon below 24 yd 35 yd O O A 420 yd B 306 yd2 OC 84 yd class=

Respuesta :

ni420
ni420 ni420
  • 14-04-2020

Answer:

21yd^2

Step-by-step explanation:

join the centre to all the vertex,

since this figure is of regular pentagon, it's will form 5 equal triangle of equal area!

now area of one such triangle is

1/2 ×base ×height

=1/2 ×3.5x2.4 (yd^2)

=4.2 yd^2

now the pentagon is sum of 5 such equal triangle,so it's are will be

5×4.2 (yd^2)

=21 yd^2

✌️:)

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