teddybear2055 teddybear2055
  • 15-04-2020
  • Mathematics
contestada

Line segment ba has endpoints b(-6,3) and a(-1,8). What are coordinates of the point located 1/5 of the way from B to A

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xero099
xero099 xero099
  • 20-04-2020

Answer:

[tex]\vec C = (-5,4)[/tex]

Step-by-step explanation:

The coordinates of the point located 1/5 of the way from B to A is:

[tex]\vec C = \vec B + \alpha \cdot \overrightarrow {BA}[/tex]

[tex]\vec C = (-6,3) + \frac{1}{5}\cdot (-1+6,8 - 3)[/tex]

[tex]\vec C = (-6,3) + \frac{1}{5}\cdot (5,5)[/tex]

[tex]\vec C = (-6,3) + (1,1)[/tex]

[tex]\vec C = (-6+1,3+1)[/tex]

[tex]\vec C = (-5,4)[/tex]

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