Answer : The value of [tex]\sin \angle N[/tex] is, 0.60
Step-by-step explanation :
Given:
In right angle triangle NPO,
∠P = 90°
ON = 5
PO = 3
NP = 4
According to trigonometric function,
[tex]\sin \theta=\frac{Perpendicular}{Hypotenuse}[/tex]
[tex]\sin \angle N=\frac{PO}{ON}[/tex]
[tex]\sin \angle N=\frac{3}{5}=0.60[/tex]
Thus, the value of [tex]\sin \angle N[/tex] is, 0.60
