Respuesta :

aabdulsamir

Answer:

994.718Hz

Explanation:

[V(rms) / I(rms)] = 2ΠfL

Vrms = 10V

Irms = 1.6A

L = 1mH = 1*10⁻³H

f = ?

[V(rms) / I(rms)] = 2ΠfL

10 / 1.6 = 2π*1*10⁻³f

6.25 = 6.28*10⁻³f

f = 994.718Hz

The frequency across the inductor is 994.718Hz

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