nightslasher245 nightslasher245
  • 15-04-2020
  • Mathematics
contestada

The radius of a cylindrical construction pipes is 2ft if the pipe is 24 ft long what is its volume

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HernanKM22 HernanKM22
  • 15-04-2020

V= (3.14)x(2²)x(24)= 301.592 ft³

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PollyP52 PollyP52
  • 15-04-2020

Answer:

96π ft^3 or  301.59 ft^3 to the nearest hundredth.

Step-by-step explanation:

Volume =  π r^2 L         (r = radius L = length).

=  π * 2^2 * 24

= 96π ft^3.

Answer Link

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