Answer:
a)-if x=7, bx+c has to be a perfect square where it's sq rt is >7.
let bx+c=64
therefore x+a=8
a=1
also 7b+c=64
all abc values are integrals
let b=2,c=50
this satisfies the equation
b) we have to solve for x here
(X+1)^2=2x+50
x^2+2x+1=2x+50
x^2=49
X=7 or x=-7
here -7 is an extraneous solution.
c)- applying some other values for ab and c.
let bx+c=81
X+a=9
a=2
if b=1, c=81-7
c=74
the new equation is x+2=√(1x+74)
