nella1223 nella1223
  • 12-05-2020
  • Mathematics
contestada

Evaluate h(x) = 2.8x3 + 0.01x2 − 1 for x = 1 and x = 2

Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 12-05-2020

Answer:

  • h(1) = 1.81
  • h(2) = 21.44

Step-by-step explanation:

Put the numbers where x is in the equation and do the arithmetic. For purposes of evaluation, it is often convenient to write the equation in Horner form:

  h(x) = (2.8x +.01)x^2 -1

Then ...

  h(1) = (2.8 +.01)·1 -1 = 1.81

  h(2) = (2.8·2 +.01)·2² -1 = 5.61·4 -1 = 21.44

__

If you have several evaluations to do, it is convenient to use a calculator or spreadsheet to do them.

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