Answer:
Explanation:
Current in a. c circuit = V / total impedance
impedance = [tex]\sqrt{(R^2+( \omega L-\frac{1}{\omega C})^2 }[/tex]
In resonance maximum current flows and for maximum current impedance should be minimum .
For it [tex]\omega L[/tex] = [tex]\frac{1}{\omega C}[/tex]
ω² = [tex]\frac{1}{LC}[/tex]
OPTION b is correct.
At resonance power is maximum because current is maximum and impedance is minimum.
OPTION c is correct.
quality factor = [tex]\frac{1}{R}\sqrt{\frac{L}{C} } }[/tex]
Option f is correct.
