Answer:
[tex]\huge\boxed{A=x^2+12x+35}[/tex]
Step-by-step explanation:
The formula of an area of a rectangle:
[tex]A=lw[/tex]
l - length
w - width
We have
[tex]l=x+7\\\\w=x+5[/tex]
Substitute:
[tex]A=(x+7)(x+5)[/tex]
Use FOIL (a + b)(c + d) = ac + ad + bc + bd
[tex]A=(x)(x)+(x)(5)+(7)(x)+(7)(5)\\\\A=x^2+5x+7x+35[/tex]
combine like terms
[tex]A=x^2+(5x+7x)+35\\\\A=x^2+12x+35[/tex]
