sadeclarke10
sadeclarke10 sadeclarke10
  • 11-06-2020
  • Mathematics
contestada

How do I solve this equation:
-5(n-1)=7(n+3)

Respuesta :

bankskamiia10
bankskamiia10 bankskamiia10
  • 11-06-2020
-5(n-1) = 7(n+3)

First, distribute the 5 in the first parentheses.

-5n+ 5 = 7(n+3)

Next, distribute the 7 in the second set of parentheses.

-5n + 5 = 7n + 21

Subtract 7n from both sides.

-5n + 5 -7n = 21

Subtract 5 from both sides.

-5n - 7n = 21 + 5

Collect like terms.

-12n = 16

Divide both sides by -12

Answer -3/4
Answer Link
ITSCAT21
ITSCAT21 ITSCAT21
  • 11-06-2020

Answer:

-3/4

Step-by-step explanation:

The First step is to distribute the 7 in the second part of parentheses.

-5+5-7n=21

-5-7n=21+5

Then collect the terms

-12n=16

Lastly distribute both sides by -12

And the answer is -3/4

Answer Link

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