Qwerty1956 Qwerty1956

14-06-2020
Mathematics

contestada

Please help. 20 points and brainliest.

Please help 20 points and brainliest class=

Respuesta :

mhanifa mhanifa

14-06-2020

Answer:

minimum -45, maximum 32

Step-by-step explanation:

C=4x-3y

x≥0, y≥4, x+y≤15

Maximum value of C can be achieved at max x and min y

min y=4 => max x=15-4=11

C=4*11-3*4= 32

Minimum value of C can be achieved at min x and max y

min x=0, max y =15

C=4*0-3*15= -45

So answer is minimum -45, maximum 32

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