tlmbryant2004
tlmbryant2004 tlmbryant2004
  • 15-06-2020
  • Mathematics
contestada

g(x)=x^3+6x^2+12x+8 determine

gxx36x212x8 determine class=

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carikoop23
carikoop23 carikoop23
  • 15-06-2020
g(-1) = 1

g(-1) = (-1)^3 + 6(-1)^2 + 12(-1) + 8

g(-1) = 1
Answer Link
LT345
LT345 LT345
  • 15-06-2020

Answer:

g(-1) = 1

Step-by-step explanation:

g(-1) = (-1)^3 + 6(-1)^2 + 12(-1) + 8

g(-1) = 1

Answer Link

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