Answer:
simplified expression for √x^2+6x+9 if x≥3
is x+3
Step-by-step explanation:
[tex]\sqrt{x^2+6x+9} \\=>\sqrt{x^2+3x+3x+9} \\=>\sqrt{x(x+3)+3(x+3)} \\=>\sqrt{(x+3)(x+3)} \\=>\sqrt{(x+3)^2}\\=>(x+3) \ or -(x+3)[/tex]
but given that x≥3
then we have to negate solution -(x+3)\
Then simplified expression for √x^2+6x+9 if x≥3
is x+3
