Answer:
(-2,-3) and (2,-3).
Step-by-step explanation:
It is given that x ∈ {-2, 0, 2} and y ∈ {-3, -1, 0, 3} .
The given equation is
[tex]y=1-x^2[/tex]
At x=-2,
[tex]y=1-(-2)^2=1-4=-3\in y[/tex]
At x=0,
[tex]y=1-(0)^2=1-0=1\notin y[/tex]
At x=2,
[tex]y=1-(2)^2=1-4=-3\in y[/tex]
Therefore, the solution of given equation are (-2,-3) and (2,-3).
