rjrjejrjrnnrnd172737 rjrjejrjrnnrnd172737
  • 14-07-2020
  • Mathematics
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PRE CALC HELP PLEASE

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Respuesta :

xKelvin
xKelvin xKelvin
  • 14-07-2020

Answer:

True.

Step-by-step explanation:

The function is indeed a polynomial. We have the single variable [tex]x[/tex] plus a constant [tex]\pi[/tex] (it's irrational, but it's still simply just a constant number). This fits the definition of polynomials.

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