martin0000 martin0000
  • 15-07-2020
  • Mathematics
contestada

Si sen α = 9/41 , el valor de P= cos α. Cotg α Ayúdenme

Respuesta :

Awais3
Awais3 Awais3
  • 15-07-2020

Answer:

P= cos  ( a ) =   40 /41

Step-by-step explanation:

your question as translated is  as

If sin α = 9/41, the value of P = cos α

As sin (a) = cos (90-a)

also sin (a) = opposite / hypotenuse

and also

Adjacent =  [tex]\sqrt{hypotenuse^{2} /opposite^{2} }[/tex]

[tex]\sqrt{41^{2} -9^{2} }[/tex]  =40

adjacent = 40

we know Cos (a) = adj/hyp

so cos(a) = 40/41 which is equal to also P.

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