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  • 15-07-2020
  • Mathematics
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Find the first four iterates of the function f(z)=z^2-2-2i with an initial value of z0=2+i

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LammettHash
LammettHash LammettHash
  • 15-07-2020

Obtain the next iterate by plugging the previous iterate into the function.

First iterate:

[tex]z_0=2+i\implies z_1=f(z_0)=(2+i)^2-2-2i=1+2i[/tex]

Second iterate:

[tex]z_2=f(z_1)=(1+2i)^2-2-2i=-5+2i[/tex]

Third iterate:

[tex]z_3=f(z_2)=(-5+2i)^2-2-2i=19-22i[/tex]

Fourth iterate:

[tex]z_4=f(z_3)=(19-22i)^2-2-2i=-125-838i[/tex]

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