A 0.675 kg mass is attached to a
spring of spring constant 42.4 N/m,
pulled, and released. What is the
frequency of the resulting
oscillation?
(Unit = Hz)

Respuesta :

Answer:

1.26

Explanation:

f=1/(2pi) square root k/m

f=1/(2pi) square root 42.4/.675

f=1.26 I just did this question and found this right