Answer:
A
Step-by-step explanation:
[tex] \frac{2003}{n} = z + \frac{23}{n} [/tex]
where z is an integer
[tex]2003 = nz + 23[/tex]
[tex]nz = 1980[/tex]
[tex]nz = {2}^{2} \times {3}^{2} \times 5 \times 11[/tex]
possible values of n
n= {1980, 990, 660, 495, 396, 330, 198, 180, 165, 132, 99, 90, 60, 45, 36, 30, 20, 18, 15, 5, 3}
cardinality of n=21
