Answer:
Step-by-step explanation:
[tex]b=\frac{fg^{2}}{dt+gy}\\\\\\b*(dt+gy) = fg^{2}\\\\\\bdt + bgy = fg^{2}\\\\\\bgy = fg^{2} - bdt\\\\\\y =\frac{fg^{2}-bdt}{bg}[/tex]
