Answer:
Step-by-step explanation:
[tex]\dfrac{3+x}3=\dfrac{20}5\\\\3+x = 4\cdot3\\\\x=12-3 \\\\x= 9[/tex] [tex]\dfrac{4+y}4=\dfrac{20}5\\\\4+y= 4\cdot4\\\\y=16-4 \\\\y=12[/tex]
[tex]\dfrac{3+x+u}3=\dfrac{60}5\\\\3+9+u=12\cdot3\\\\u=36-12 \\\\u=24[/tex] [tex]\dfrac{4+y+v}4=\dfrac{60}5\\\\4+12+v=12\cdot4\\\\v=48-16 \\\\v=32[/tex]
