marisamanzanar
marisamanzanar marisamanzanar
  • 15-08-2020
  • Mathematics
contestada

In the diagram of O, m∠JOK = 60° and OJ = 6 in. What is the exact area of the shaded region?

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tramserran
tramserran tramserran
  • 15-08-2020

Answer:   6π

Step-by-step explanation:

Area of a circle is π r².

Area of a section of a circle is π r² × the section of the circle.

[tex]A=\pi r^2\bigg(\dfrac{\theta}{360^o}\bigg)[/tex]

Given: r = 6, Ф = 60°

[tex]A=\pi (6)^2\bigg(\dfrac{60^o}{360^o}\bigg)\\\\\\.\quad =\pi (6)^2\bigg(\dfrac{1}{6}\bigg)\\\\\\.\quad =6\pi[/tex]

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