Answer:
[tex]\Huge \boxed{\mathrm{B. \ 6}}[/tex]
Step-by-step explanation:
We can apply the Intersecting Secant-Tangent Theorem.
TV is the secant.
VW is the tangent.
VW² = VT × VU
(x+6)² = (5+x+4) × (x+4)
Combine the terms in bracket.
(x+6)² = (x+9)(x+4)
Expand brackets on both sides of the equation.
x²+12x+36=x²+13x+36
Subtract x² from both sides.
12x+36=13x+36
Subtract 12x from both sides.
36=x+36
Subtract 36 from both sides.
0=x
WV = x+6
x=0
WV = 0+6 = 6
The measure of the tangent WV is 6.
