ITSyoGrlBri
ITSyoGrlBri ITSyoGrlBri
  • 11-09-2020
  • Mathematics
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The expression (y^20) (y^-5)^2 is equivalent to y^n. What is the value of n? n = 27 n = 10 n = -200 n = 17

Respuesta :

jimrgrant1 jimrgrant1
  • 11-09-2020

Answer:

n = 10

Step-by-step explanation:

Using the rules of exponents

[tex]a^{m}[/tex] × [tex]a^{n}[/tex] ⇔ [tex]a^{(m+n)}[/tex]

[tex](a^{m}) ^{n}[/tex] = [tex]a^{mn}[/tex]

Given

([tex]y^{20}[/tex] ) ([tex](y^{-5}) ^{2}[/tex]

= [tex]y^{20}[/tex] × [tex]y^{-10}[/tex]

= [tex]y^{(20-10)}[/tex]

= [tex]y^{10}[/tex] → in the form [tex]y^{n}[/tex] with n = 10

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