njoodh2005
njoodh2005 njoodh2005
  • 14-09-2020
  • Mathematics
contestada

Differentiate y=(sinx)(3x^2) please help please !

Respuesta :

jimrgrant1 jimrgrant1
  • 14-09-2020

Answer:

6xsinx + 3x²cosx

Step-by-step explanation:

Differentiate using the product rule

Given y = f(x)(g(x) , then

[tex]\frac{dy}{dx}[/tex] = f(x)g'(x) + g(x)f'(x)

Here f(x) = sinx ⇒ f'(x) = cosx

g(x) = 3x² ⇒ g'(x) = 6x

Thus

[tex]\frac{dy}{dx}[/tex] = 6xsinx + 3x²cosx

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