Answer:
(fog)(x) = f(g(x)) = 3(x^2 + 1 ) + 2
Step-by-step explanation:
For this problem, you simply need to understand the notation (fog)(x) is equivalent to f ( g ( x ) ). This means you simply plug the function g(x) into each x within the function of f(x). Let's do this:
f(x) = 3x + 2
g(x) = x^2 + 1
f(g(x)) = 3(x^2 + 1 ) + 2
(fog)(x) = f(g(x))
Cheers.
