annadircksen annadircksen
  • 15-09-2020
  • Mathematics
contestada

What is the slope of a line perpendicular to the line whose equation is 3x-12y=2163x−12y=216.

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ZoeL833 ZoeL833
  • 15-09-2020

Answer:

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Step-by-step explanation:

Here 3x-12y-216=0

Reducing into slope intercept form

-12y= -3x + 216

12y = 3x - 216

Which is in the form of, y = mx + c

Slope (m) = 3

Step-by-step explanation:

Answer Link
ffernandez337 ffernandez337
  • 15-09-2020

Answer:

Slope (m) = 3

Step-by-step explanation:

Here 3x-12y-216=0

Reducing into slope intercept form

-12y= -3x + 216

12y = 3x - 216

Which is in the form of, y = mx + c

Slope (m) = 3

Answer Link

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