sarasejernielsen sarasejernielsen
  • 11-10-2020
  • Mathematics
contestada

A rectangle is 12 cm longer than it is wide. If its length and width are both decreased by 2 cm, its area is decreased by 108 cm². Find its original dimensions.

Respuesta :

nonoisomgcool1
nonoisomgcool1 nonoisomgcool1
  • 11-10-2020

Let the width be "x" cm.

Then the length is "x+12" cm

And the area = x(x+12) = x^2+12x cm^2

----------------------------

Change the dimensions:

width = "x-2" cm

length = "x+10" cm

New area = (x-2)(x+10) = x^2 + 8x - 20 cm^2

------------------

Equations :

Old area - New area = 108 cm^2

x^2+12x -(x^2 + 8x - 20) = 108

4x + 20 = 108

4x = 88

x = 22 cm (original width)

x+12 = 24 cm (original length)

Answer Link

Otras preguntas

What is the inverse of f(x)= cube root of x +2.
The results of creating a more cohesive political confederacy for the Iroquois included
What are thoooooooooose
Three friends go bowling. The cost per person per game is $5.30. The cost to rent shoes is $2.50 per person. Their total cost is $55.20. How many games did they
Solve 10a-5b=25 for b
9x + 3y = 12 in function notation form
numbers between 61 and 107 that is a multiple of 3, 6, and 8
Is diet Pepsi heterogeneous or is it homogeneous
Andrew invested $20,000 in mutual funds and received a sum of $35,000 at the end of the investment period. Calculate the ROI. I need the perentage...
Solve. 5 = –(–z + 3) a. –8 b. 8 c. –2 d. 2