Respuesta :

gmany

Answer:

[tex]\huge\boxed{a=36;\ b=-9}[/tex]

Step-by-step explanation:

[tex](6x-3)(6x+3)=ax^2+b\qquad|\text{use}\ (a-b)(a+b)=a^2-b^2\\\\(6x)^2-3^2=ax^2+b\\\\6^2x^2-9=ax^2+b\\\\36x^2-9=ax^2+b\Rightarrow a=36;\ b=-9[/tex]