DestinyCamilaaa
DestinyCamilaaa DestinyCamilaaa
  • 15-10-2020
  • Mathematics
contestada

Does anyone know how to solve this 5x(x+4)^2-2y^5 x=-3 and y=-2

Respuesta :

layiah55
layiah55 layiah55
  • 15-10-2020
It’s 49.
5(-3)(-3+4)^2 -2(-2^5)
5(-3)x 1^2 +2^6
5(-3) x 1 +64
-15+64
=49
Answer Link
merrilbiju merrilbiju
  • 15-10-2020

Answer:

49

Step-by-step explanation:

Answer Link

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