Answer:
The answer is
3.75 × 10²⁴ atoms of Al
Explanation:
To find the number of atoms of Al given it's number of moles we use the formula
N = n × L
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question
n = 6.23 mol
We have
N = 6.23 × 6.02 × 10²³
We have the final answer as
3.75 × 10²⁴ atoms of Al
Hope this helps you
