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11-11-2020
Mathematics

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plsss helpppp 6x^2+4x-42

Respuesta :

virtuematane virtuematane

11-11-2020

Answer:

Step-by-step explanation:

6x^2+4x-42

2(3x^2+2x-21)=0

3x^2+2x-21=0

3x^2+(9-7)x-21=0

3x^2+9x-7x-21=0

3x(X+3)-7(X+3)=0

(3X-7)(X+3)=0

So Answer is (3x-7)(X+3)

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