Answer:
[tex]x=\frac{ln(17)}{ln(2)}[/tex]
Step-by-step explanation:
Use natural log ln() to move down the exponent.
[tex]2^x=17[/tex]
[tex]ln(2^x)=ln(17)[/tex] you can move the exponent outside of ln()
[tex]xln(2)=ln(17)[/tex]
[tex]x=\frac{ln(17)}{ln(2)}[/tex]
Type that in your calculator and you should get teh answer. I don't have a calculator with me so i can't do it.
