Answer:
[tex]\sqrt{\frac{3x}{3} } + \frac{10}{109} x[/tex]
Step by step:
[tex]\sqrt{x-\frac{3}{7}[/tex] = [tex]\sqrt{\frac{49x-21}{7} }[/tex]
[tex]\sqrt{\frac{49x-21}{7} }[/tex] ÷ 12x+7=[tex]\sqrt{\frac{7x-3x}{12}} + 7[/tex]
[tex]\sqrt{\frac{7x-3x}{12}} + 7[/tex] ÷ 76.3x = [tex]\sqrt{\frac{3x}{3} } + \frac{10}{109} x[/tex]
Hope this helps!
