Answer:
(2, 9)
Step-by-step explanation:
[tex]y=-x^2+4x+5\quad \implies\quad a=-1\,,\ b=4\,,\ c=5\\\\h=\dfrac{-b}{2a}=\dfrac{-4}{2(-1)}=2\\\\k=c-\dfrac{b^2}{4a}=5-\dfrac{4^2}{4(-1)}=5-\dfrac{16}{-4}=5+4=9[/tex]
Or by completing the square:
[tex]y=-x^2+4x+5\\\\y=-(x^2-4x)+5\\\\y=-(\underline{x^2-2\cdot x\cdot 2+2^2}-2^2)+5\\\\y=-\left((x-2)^2-4\right)+5\\\\y=-(x-2)^2+4+5\\\\y=-(x-2)^2+9\quad\implies\quad h=2\,,\ k=9[/tex]
