Answer:
30 g/mol
Explanation:
Step 1: Given data
- Volume of the gas at NTP: 11.2 L
Step 2: Calculate the moles corresponding to 11.2 L of gas
At normal temperature and pressure (1 atm, 293.15 K), 1 mol of a gas has a volume of 24.05 L.
11.2 L × 1 mol/24.05 L = 0.466 mol
Step 3: Calculate the molecular mass of the gas
0.466 moles of the gas weigh 14 g. The molecular mass is:
M = 14 g/0.466 mol = 30 g/mol
