maryamchaduary52 maryamchaduary52
  • 13-12-2020
  • Chemistry
contestada

What is the molarity of a solution prepared by dissolving 1.25g of HCl gas
into enough water to make 30cm3 of solution

Respuesta :

ardni313
ardni313 ardni313
  • 16-12-2020

The molarity of a solution : 1.13 M

Further explanation

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

[tex]\large \boxed {\bold {M ~ = ~ \dfrac {n} {V}}}[/tex]

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

mass HCl = 1.25 g

mol HCl(MW=36.5 g/mol) :

[tex]\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{1.25}{36.5}\\\\mol=0.034[/tex]

Volume of solution = 30 cm³ = 0.03 L

The molarity :

[tex]\tt M=\dfrac{0.034}{0.03}\\\\M=1.13[/tex]

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