Answer:
Q = 100.42 J
Explanation:
Given data:
Mass of water = 1.500 g
Specific heat capacity of water = 4.184 J/g.°C
Heat required = ?
Initial temperature = 23°C
Final temperature = 39°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 39°C - 23°C
ΔT = 16°C
Q = 1.500 g× 4.184 J/g.°C ×16°C
Q = 100.42 J
