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Answer:

E = 21.22×10⁻⁴⁵ J

Explanation:

Given data:

Frequency of photon = 3.20×10⁻¹¹ s⁻¹

Energy of photon = ?

Solution:

Formula:

E = h×f

h = plancks  constant = 6.63×10⁻³⁴ Js

by putting values,

E = 6.63×10⁻³⁴ Js × 3.20×10⁻¹¹ s⁻¹

E = 21.22×10⁻⁴⁵ J

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