AdannaPena17 AdannaPena17

12-01-2021
Physics

contestada

What is the student's kinetic energy at the bottom of the hill if he is moving
at 18 m/s?
Variables:
Show Work

Respuesta :

helinwang helinwang

12-01-2021

Answer:

KE = 10530 J or 10.53 KJ

Explanation:

The formula for kinetic energy is KE = 1/2 mv^2

Let's apply the formula:

KE = 1/2 mv^2

KE = 1/2 (65kg) (18m/s)^2

KE = 10530 J or 10.53 KJ

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