Answer:
The length of the simple pendulum is 0.248 m.
Explanation:
Given;
period of the simple pendulum, T = 1.00 s
let the length of the simple pendulum = L
The period of oscillation of a simple pendulum is calculated as;
[tex]T = 2\pi \sqrt{\frac{l}{g} } \\\\\frac{T}{2\pi } = \sqrt{\frac{l}{g} }\\\\\frac{T^2}{4\pi ^2 } = \frac{l}{g}\\\\l = \frac{gT^2}{4\pi ^2 } \\\\l = \frac{(9.8)(1)^2}{4\pi ^2 } \\\\l = 0.248 \ m[/tex]
Therefore, the length of the simple pendulum is 0.248 m.
