Answer:
Explanation:
For an incline projection made at angle of θ , expression of horizontal range R can be given by the following equation .
R = u² sin 2θ / g
u is initial velocity of throw .
For range R to be maximum , the value of sin 2θ must be maximum . The maximum value of sin of an angle is 1 , so
For maximum R ,
sin2θ = 1 = sin90
2θ = 90 .
θ = 45⁰ .
So for projection made at 45⁰ , horizontal range is maximum .
