The mass of sodium hydroxide will be "30 g".
Given values are:
- Volume, V = 1.0 L or, 1000 mL
- Solution, M = 0.75 M
As we know the relation,
→ [tex]M = \frac{W}{GM}\times \frac{1000}{V}[/tex]
or,
→ [tex]W = \frac{M\times GM\times V}{1000}[/tex]
By substituting the values, we get
[tex]= \frac{0.75\times 40\times 1000}{1000}[/tex]
[tex]= 30 \ g[/tex]
Thus the above response is right.
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