annisanfieldottor07
annisanfieldottor07 annisanfieldottor07
  • 14-02-2021
  • Mathematics
contestada

Pls help me. To be submitted tomorrow​

Pls help me To be submitted tomorrow class=

Respuesta :

trinityboyle
trinityboyle trinityboyle
  • 14-02-2021

Answer:

The value of your equation would be 371/30

Step-by-step explanation:

Given tanθ=8/15 - -(1)

sec^2θ

= 1+tan^2θ

= 1+(8/15)^2

= 1+64/225

= 225+64/225

= 289/225

=17^2+15^2

Now, secθ = [tex]\sqrt{\frac{17^2}{15^2} }[/tex]

= 17/15

Cosθ = 15/17 - -(2)

Value of sinθ+cosθ/cosθ(1-cosθ)

Dividing numerator and denominator by cosθ, we get

= sinθ+cosθ/cosθ/cosθ(1-cosθ)/cosθ

= (sinθ/cosθ+cosθ/cosθ)/(1-cosθ)

= tanθ - 1/1-cosθ

= 8/15 + 1/1-15/17

= 8+15/15/17-15/17

= 23/15/2/17

= 23/15 x 17/2

= 371/30

Hope this helps!

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