Answer:
26500 W/m²
Explanation:
Given that:
The diameter of the dish d = 1.2 m
Assuming the Solar power P capture by the dish = 1300 W
The surface area of the pot is calculated by using the formula:
[tex]= \pi r^2[/tex]
[tex]\pi \dfrac{d^2}{4}[/tex]
where; the diameter = 25 cm
Area = [tex]\pi \dfrac{d^2}{4}[/tex]
Area = [tex]\pi \dfrac{0.25^2}{4}[/tex]
Area = 0.049 m²
The intensity is calculated by using the formula
I = power/area
I = 1300/0.049
I = 26530.6 W/m²
I ≅ 26500 W/m²
